Eureka Math Grade 5 Module 2 Lesson 18 Answer Key (2024)

Engage NY Eureka Math 5th Grade Module 2 Lesson 18 Answer Key

Eureka Math Grade 5 Module 2 Lesson 18 Problem Set Answer Key

Question 1.
Estimate the quotients for the following problems. The first one is done for you.

a. 5,738 ÷ 21
≈ 6,000 ÷ 20
= 300

Answer:
6000/20 = 300.

Explanation:
In the above-given question,
given that,
5738/21.
6000/20.
300.

b. 2,659 ÷ 28
≈ ___3000______ ÷ ____30_____
= ___100______

Answer:
3000/30 = 100.

Explanation:
In the above-given question,
given that,
2659/28.
3000/30.
100.

c. 9,155 ÷ 34
≈ ____9000_____ ÷ ___30______
= ____300_____

Answer:
9000/30 = 300.

Explanation:
In the above-given question,
given that,
9155/34.
9000/30.
100.

d. 1,463 ÷ 53
≈ ___1000______ ÷ _____50____
= _____200____

Answer:
1000/20 = 50.

Explanation:
In the above-given question,
given that,
1463/53.
1000/50.
200.

e. 2,525 ÷ 64
≈ ___2000______ ÷ _____60____
= ___33______

Answer:
2000/60 = 33.

Explanation:
In the above-given question,
given that,
2525/64.
2000/60.
33.

f. 2,271 ÷ 72
≈ __2000_______ ÷ ____70_____
= ____28_____

Answer:
2000/70 = 28.

Explanation:
In the above-given question,
given that,
2271/72.
2000/70.
28.

g. 4,901 ÷ 75
≈ __5000_______ ÷ ___75______
= ___66______

Answer:
5000/75 = 66.

Explanation:
In the above-given question,
given that,
4901/75.
5000/75.
66.

h. 8,515 ÷ 81
≈ __8000_______ ÷ ___80______
= __100_______

Answer:
8000/80 = 100.

Explanation:
In the above-given question,
given that,
8515/81.
8000/80.
100.

i. 8,515 ÷ 89
≈ ___8000______ ÷ ___90______
= ___88______

Answer:
8000/90 = 88.

Explanation:
In the above-given question,
given that,
8515/89.
8000/90.
88.

j. 3,925 ÷ 68
≈ ___4000______ ÷ ___70______
= ____57_____

Answer:
4000/70 = 57.

Explanation:
In the above-given question,
given that,
3925/68.
4000/70.
57.

k. 5,124 ÷ 81
≈ ___5000______ ÷ ____80_____
= __62_______

Answer:
5000/80 = 62.

Explanation:
In the above-given question,
given that,
5124/81.
5000/80.
62.

l. 4,945 ÷ 93
≈ ___5000______ ÷ ___90______
= ____55_____

Answer:
5000/90 = 55.

Explanation:
In the above-given question,
given that,
4945/93.
5000/90.
55.

m. 5,397 ÷ 94
≈ __5000_______ ÷ ___90______
= _____55____

Answer:
5000/90 = 55.

Explanation:
In the above-given question,
given that,
5397/94.
5000/90.
55.

n. 6,918 ÷ 86
≈ ___7000______ ÷ ___90______
= _____78____

Answer:
7000/90 = 78.

Explanation:
In the above-given question,
given that,
6918/86.
7000/86.
78.

o. 2,806 ÷ 15
≈ __2900_______ ÷ ___10______
= ___290______

Answer:
2900/10 = 290.

Explanation:
In the above-given question,
given that,
2806/15.
2900/10.
290.

Question 2.
A swimming pool requires 672 ft2 of floor space. The length of the swimming pool is 32 ft. Estimate the width of the swimming pool.

Answer:
The width of the swimming pool = 21 ft.

Explanation:
In the above-given question,
given that,
A swimming pool requires 672 sq ft of floor space.
The length of the swimming pool is 32 ft.
672/32 = 21ft.
the width of the swimming pool = 21 ft.

Question 3.
Janice bought 28 apps for her phone that, altogether, used 1,348 MB of space.
a. If each app used the same amount of space, about how many MB of memory did each app use? Show how you estimated.

Answer:
The estimated memory = 48 MB.

Explanation:
In the above-given question,
given that,
Janice bought 28 apps for her phone that, altogether, used 1348 MB of space.
1348/28 = 48 MB.
The estimated memory = 48 MB.

b. If half of the apps were free and the other half were $1.99 each, about how much did she spend?

Answer:
The amount she spends = $677.

Explanation:
In the above-given question,
given that,
If half of the apps were free and the other half were $1.99 each.
1348/1.99 = $677.

Question 4.
A quart of paint covers about 85 square feet. About how many quarts would you need to cover a fence with an area of 3,817 square feet?

Answer:
The quarts would you need to cover a fence = 45 ft.

Explanation:
In the above-given question,
given that,
A quart of paint covers about 85 square feet.
area = 3817 sq ft.
3817/85 = 45 ft.

Question 5.
Peggy has saved $9,215. If she is paid $45 an hour, about how many hours did she work?

Answer:
The many hours did she work = $205.

Explanation:
In the above-given question,
given that,
Peggy has saved $9215.
If she is paid $45 an hour.
$9215/45.
205.
The many hours did she work = $205.

Eureka Math Grade 5 Module 2 Lesson 18 Exit Ticket Answer Key

Estimate the quotients for the following problems.

a. 6,523 ÷ 21
≈ __6000_______ ÷ ___20______
= __300_______

Answer:
6000/20 = 300.

Explanation:
In the above-given question,
given that,
6000/20.
6000/20.
300.

b. 8,491 ÷ 37
≈ ___8000______ ÷ ___40______
= __200_______

Answer:
8000/40 = 200.

Explanation:
In the above-given question,
given that,
8491/37.
8000/40.
200.

c. 3,704 ÷ 53
≈ __4000_______ ÷ __50_______
= ____80_____

Answer:
4000/50 = 80.

Explanation:
In the above-given question,
given that,
3704/53.
4000/50.
80.

d. 4,819 ÷ 68
≈ ___5000______ ÷ ___70______
= ___71______

Answer:
5000/90 = 70.

Explanation:
In the above-given question,
given that,
4819/68.
5000/70.
71.

Eureka Math Grade 5 Module 2 Lesson 18 Homework Answer Key

Question 1.
Estimate the quotients for the following problems. The first one is done for you.
a. 8,328 ÷ 41
≈ 8,000 ÷ 40
= 200

b. 2,109 ÷ 23
≈ ___2000______ ÷ ____20_____
= ___100______

Answer:
2000/20 = 100.

Explanation:
In the above-given question,
given that,
2000/20.
2000/20.
100.

c. 8,215 ÷ 38
≈ __8000_______ ÷ ___40______
= ____200_____

Answer:
8000/40 = 200.

Explanation:
In the above-given question,
given that,
8215/38.
8000/40.
200.

d. 3,861 ÷ 59
≈ ___4000______ ÷ ____60_____
= ____67____

Answer:
4000/60 = 67.

Explanation:
In the above-given question,
given that,
3861/59.
4000/60.
67.

e. 2,899 ÷ 66
≈ ___3000______ ÷ ____70_____
= ___43______

Answer:
3000/70 = 43.

Explanation:
In the above-given question,
given that,
2899/66.
3000/70.
43.

f. 5,576 ÷ 92
≈ ___6000______ ÷ ___100______
= ___60______

Answer:
6000/100 = 60.

Explanation:
In the above-given question,
given that,
5576/92.
6000/100.
60.

g. 5,086 ÷ 73
≈ ___5000______ ÷ ___70______
= ___71______

Answer:
5000/70 = 71.

Explanation:
In the above-given question,
given that,
5086/73.
5000/70.
71.

h. 8,432 ÷ 81
≈ __8000_______ ÷ _____80____
= __100_______

Answer:
8000/80 = 100.

Explanation:
In the above-given question,
given that,
8432/81.
8000/80.
100.

i. 9,032 ÷ 89
≈ __9000_______ ÷ _____90____
= ____1000_____

Answer:
9000/90 = 100.

Explanation:
In the above-given question,
given that,
9032/89.
9000/90.
1000.

j. 2,759 ÷ 48
≈ ___3000______ ÷ _____50____
= __60_______

Answer:
3000/50 = 60.

Explanation:
In the above-given question,
given that,
2759/48.
3000/50.
60.

k. 8,194 ÷ 91
≈ ___8000______ ÷ ____90_____
= ____89_____

Answer:
8000/90 = 89.

Explanation:
In the above-given question,
given that,
8194/91.
8000/90.
89.

l. 4,368 ÷ 63
≈ __4000_______ ÷ ___60______
= ____67_____

Answer:
4000/60 = 67.

Explanation:
In the above-given question,
given that,
4368/63.
4000/60.
67.

m. 6,537 ÷ 74
≈ __6000_______ ÷ ___70______
= ____86_____

Answer:
6000/70 = 86.

Explanation:
In the above-given question,
given that,
6537/74.
6000/70.
86.

n. 4,998 ÷ 48
≈ ___5000______ ÷ ___50______
= ___100______

Answer:
5000/50 = 100.

Explanation:
In the above-given question,
given that,
4998/48.
5000/50.
100.

o. 6,106 ÷ 25
≈ __6000_______ ÷ ___20______
= ___300______

Answer:
6000/25 = 300.

Explanation:
In the above-given question,
given that,
6106/25.
6000/20.
300.

Question 2.
91 boxes of apples hold a total of 2,605 apples. Assuming each box has about the same number of apples, estimate the number of apples in each box.

Answer:
The number of apples in the box = 29 boxes.

Explanation:
In the above-given question,
given that,
91 boxes of apples hold a total of 2,605 apples.
2605/91 = 29 boxes.
The number of apples in the box = 29 boxes.

Question 3.
A wild tiger can eat up to 55 pounds of meat in a day. About how many days would it take for a tiger to eat the following prey?

Prey

Weight of Prey

Number of Days

Eland Antelope

1,754 pounds32 days

Boar

661 pounds12 days
Chital Deer

183 pounds

3 days
Water Buffalo

2,322 pounds

42 days

Answer:
Eland Antelope = 32 days.
Boar = 12 days.
Chital Deer = 3 days.
Water Buffalo = 42 days.

Explanation:
In the above-given question,
given that,
A wild tiger can eat up to 55 pounds of meat in a day.
Eland Antelope = 32 days.
Boar = 12 days.
Chital Deer = 3 days.
Water Buffalo = 42 days.

Eureka Math Grade 5 Module 2 Lesson 18 Answer Key (2024)

FAQs

What grade does Eureka math go up to? ›

Eureka Math® is a holistic Prekindergarten through Grade 12 curriculum that carefully sequences mathematical progressions in expertly crafted modules, making math a joy to teach and learn. We provide in-depth professional development, learning materials, and a community of support.

What are the four core components of a Eureka Math TEKS lesson? ›

A typical Eureka lesson is comprised of four critical components: fluency practice, concept development (including a problem set), application problem, and student debrief (including the Exit Ticket).

What type of math is Eureka math? ›

Eureka Math® is a math program designed to advance equity in the math classroom by helping students build enduring math knowledge. What's in the Program? Numbers should add up to more than the right answer.

How was Eureka Math created? ›

In 2012 the New York State Education Department contracted with the organization that would become Great Minds to create an open educational resource (OER) math program for K–12 educators. We wrote EngageNY Math, and over time we developed that program into Eureka Math.

What is the hardest math in 5th grade? ›

Some of the hardest math problems for fifth graders involve multiplying: multiplying using square models, multiplying fractions and whole numbers using expanded form, and multiplying fractions using number lines.

What is the hardest math grade? ›

Generally speaking, the most rigorous math courses in high school include Advanced Placement (AP) Calculus AB and BC, AP Statistics, and for some, Multivariable Calculus (which might be offered at your school or at a local college).

What is the Eureka lesson breakdown? ›

Each lesson in A Story of Units is comprised of four critical components: fluency practice, concept development (including the problem set), application problem, and student debrief (including the Exit Ticket).

Is Eureka math based on common core? ›

Eureka Math is a Common Core math. Eureka Math's framework is entirely built on the Common Core Learning Standards and Progressions for the Common Core State Standards in Mathematics.

What are the goals of Eureka Math? ›

Eureka Math is designed to support students in gaining a solid understanding of concepts, a high degree of procedural skill and fluency, and the ability to apply math to solve problems in and outside the classroom. There is also an intentional coherence linking topics and thinking across grades.

Why are schools using Eureka Math? ›

Eureka Math, a Common Core-aligned curriculum published by the non-profit Great Minds Inc., equates mathematical concepts to stories, with the aim of developing conceptual understanding.

Who is the father of math Eureka? ›

Here's a closer look into this sudden discovery (the “Eureka!” moment): The famous Greek mathematician, physicist, and astronomer, Archimedes was born in 287 BC in Syracuse, a Greek colony in Sicily (an island now part of Italy).

What is the difference between Eureka Math and Eureka Math 2? ›

Eureka Math-Squared is the newest version of a math curriculum that EE teachers were already using. The difference, Karsteter explained, is that in the new version being implemented this year, everything is simplified.

Who was the first math magician? ›

The name "mathemagician" was probably first applied to Martin Gardner, but has since been used to describe many mathematician/magicians, including Arthur T. Benjamin, Persi Diaconis, and Colm Mulcahy.

Who taught Archimedes math? ›

As a young man, Archimedes may have studied in Alexandria with the mathematicians who came after Euclid. It is very likely that there he became friends with Conon of Samos and Eratosthenes of Cyrene.

What is the highest level of math in 9th grade? ›

9th grade math usually focuses on Algebra I, but can include other advanced mathematics such as Geometry, Algebra II, Pre-Calculus or Trigonometry.

What is 8th grade advanced math? ›

Students on the advanced math track will take Algebra. This standards-based class covers the second half of Math 8 as well as high school-level Algebra I and is designed to prepare students for geometry in ninth grade. Placement is based on prior grades, teacher recommendations, and district benchmark testing scores.

What grade level does prodigy math go up to? ›

With 1,500+ curriculum-aligned math skills for 1st to 8th grade, Prodigy Math is so much more than a game. Prodigy Math is an engaging game-based learning platform that's dedicated to improving students' confidence and achievements in math.

What is the highest math class ever? ›

Math 55 is a two-semester freshman undergraduate mathematics course at Harvard University founded by Lynn Loomis and Shlomo Sternberg. The official titles of the course are Studies in Algebra and Group Theory (Math 55a) and Studies in Real and Complex Analysis (Math 55b).

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